QBJohnnywas
November 13 2006 8:36 AM EST
Ok. I have AMF. According to the Wiki and using Sutekh's char for example purposes who has an FB of 3.3 million, I would require an AMF of 3.3 million to hit that FB for 50% retaliation. Also according to the Wiki I would need approx 33 million to hit that FB for 100% and shutdown.
But is there a way of working out other percentages? How much AMF would I need for 10%, 20% and so on...?
If it helps, my AMF of 671,000 hits him for 0.14.
QBJohnnywas
November 13 2006 11:48 AM EST
That does help actually. Thanks!
QBsutekh137
November 13 2006 12:23 PM EST
And just so you know, my effective fireball is:
Fireball: 4,290,000/3,300,000 (543,588)
Interestingly enough, 671000/4290000 is 0.15641. The AMF registered for 0.14. With just a few more data points, we could plot that curve pretty easily.
Mine is (0.18) with a level 1,000,000 level amf.
Miandrital
November 16 2006 4:58 PM EST
The wiki is actually wrong. After testing during the free untrain week I found that you would need over 450 mil AMF to hit that FB for 1.00. This was the testing from the post I made during the untrain week:
Tigah cast Antimagic Field on Sakura (0.97) at x20
Tigah cast Antimagic Field on Sakura (0.98) at x30
Tigah cast Antimagic Field on Sakura (0.99) at x40
Tigah cast Antimagic Field on Sakura (0.99) at x50
Tigah cast Antimagic Field on Sakura (0.99) at x60
Tigah cast Antimagic Field on Sakura (0.99) at x70
Tigah cast Antimagic Field on Sakura (0.99) at x80
Tigah cast Antimagic Field on Sakura (0.99) at x90
Tigah cast Antimagic Field on Sakura (0.99) at x100
Tigah cast Antimagic Field on Sakura (1.00) at x110
(x20 would be an AMF 20 times greater than the DD spell. The spell was a base decay.)
AdminShade
November 16 2006 5:18 PM EST
I actually also done (basic) some testing on AMF and it should be listed on cbstuff.....
The Vampyre cast Antimagic Field on Joe (0.19)
Antimagic Field: 1,041,986/883,039
Has sut raised his FB since his last post?
I have a possible equation to generate the effective AMF. It's simple enough to be implemented, but if this is what Jon's using, I'm really impressed with his deviousness.
I need a few old-timers to help me check this. Let me know.
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