Arrow Merging Costs? (in General)
January 26 2007 1:16 PM EST
Any reason why when you merge arrows of equal value it always gives you the option of "Free" and "Cost: $X" where X = the number of bundles of arrows you're merging? There seems to be no benefit to paying $2 (or $3 or $4 depending on your bundles) to merge them.
January 26 2007 1:17 PM EST
This bug has been here for a while, just do the free option.
January 26 2007 1:49 PM EST
Do the one that'll cost ya a couple bucks :) It won't gain ya anything, but it makes it so that the blacksmith doesnt think you're a cheap-skate :P
i do it alll the time for fun :P
January 26 2007 2:30 PM EST
Yippee! I just wasted $3 CB2! Such fun!
Though it sounds like i'm making fun of you, or calling you a moron, I've never done the free option myself :P
January 26 2007 4:00 PM EST
I always paid extra, in case the bug favor the can-afford-$3er...
really tho, what is $3 cb
January 27 2007 3:25 AM EST
or $1 cb + $1 cb + $1 cb :p
January 27 2007 6:23 AM EST
or $4 cb - $1 cb
January 27 2007 2:06 PM EST
6CB/2 also works here...
This thread is closed to new posts.
However, you are welcome to reference it
from a new thread; link this with the html
<a href="/bboard/q-and-a-fetch-msg.tcl?msg_id=0020xs">Arrow Merging Costs?</a>