Okay, either I'm crazy, or the website has the wrong answer. I got 2.04. The question is calculate the pH of .13M HF. HF's Ka is 6.8x10^-4.
Yeah, I too got 2.03 and we just went over this stuff in class
Haha, missed a - and got 2.03.. then added the negative and got 2.04
Evidently our book had 3.5*10^-4.
March 28 2010 10:26 PM EDT
Maybe you could try this:
Components of the solution (mixture):
Initial concentration = 0.13
Ka1 = 0.00035 ( pKa1 = 3.4559319556497 )
[H+] = 0.0065726402681321
[OH-] = 1.5214585907715E-12
pH = 2.1822601367506
pOH = 11.817739863249
March 28 2010 10:55 PM EDT
Chem=worst subject ever.
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