# Find the next number. (trick question :P) (in Contests)

This is the sequence: 3,6,9,12,15,__

What's the next number? This is a trick question, so please do not say 18.

If you think of a number, please say the sequence you used.

For example, if you thought it was 18, say the sequence is 3(n) where n is the # term of the sequence.

There are an infinite amount of answers. (I'm not joking.)

Winner gets 100K. Or whoever gives the most satisfactory answer..

##
*Mikel*
December 22 2007 11:08 AM EST

I'll go with 30, since you said 18 is incorrect.

I'm a going by the fact that you listed out a sequence and the next step would be to add 15 to the sequence of numbers.

##
*AdminShade*
December 22 2007 11:09 AM EST

x = 3n in which x is your answer and n is a whole number to give your answers.

Trick question? Indeed because you gave the answer yourself already :p

((((9956512 - 9956496) * 3) - 3) / 3)

##
*toitle*
December 22 2007 11:16 AM EST

18...the sum of the digits can be reduced to a cycling pattern of 3, 6, 9. 18(1+8=90, 21(2+1=3), 24(2+4=6), etc...

##
*toitle*
December 22 2007 11:17 AM EST

or alternatively...42, the answer is 42

##
*[P]Mitt*
December 22 2007 11:20 AM EST

The next number is pi.

Sequence is:

3(n) for n<5, where n is the # term of the sequence

0.523598776(n), where n>6

##
*Yukk*
December 22 2007 12:17 PM EST

Well, I'd have to guess 123456789 since, if there's an infinite number of answers, then possibly, your sequence is just random numbers which appear to have some relationship to each other.

##
*Windwalker*
December 22 2007 12:32 PM EST

21 ;)

π=3.14159265358979323846264338327950288419716939937510.

I like pi.(e)

;)

Uh, just remove the π=

Sorry! :)

I'm going to go with Yukk here. If there's an infinite amount of answers, every number must be an answer. So it doesn't matter what number you say.

the answer hmmmm

3x6

3+15

or any other fathomed equation possible that will equal the next number.

use an algorithm would be best :P

##
*Lochnivar*
December 22 2007 3:35 PM EST

I like toitle's theory on the total of the digits cycling (3, 6,9, 3, 6,....)

So I'll pick 9,000,000 or maybe 108 or 2070..

OH I see.

I really like that theory, it's very clever!

37. They are lottery numbers.

mikel, I never said that you add 15 for the next number of the sequence.

mitt, your sequence says >6, so I don't know what happens at 6, so.. sorry technical issue. just patch it up :)

I never said you couldn't use 3(n), so I guess I have to give shade 100K.. :(

I like toitle's answer, so he gets 100K too.

neither of these winning sequences will be accepted as a correct answer anymore. nor will sequences from these two winners. (gotta make this fair :P mwahahaha!)

you cannot use someone else's sequence (the first to post the sequence gets the credit) and PLEASE! make a sequence to go with your answer!

I'm still looking for a good sequence, so that 100K's still there.

Meteor Hawk (Tinred Iaeun) 141.155.11.57 toitle (Kree) $100000 9:25 PM EST

Meteor Hawk (Tinred Iaeun) 141.155.11.57 AdminShade (Children of Hurin) $100000 9:30 PM EST

I'll post the sequence when someone wins. :)

oh, and it's not the lottery numbers.

##
*j'bob*
December 22 2007 9:54 PM EST

27

3 (+) 6 (=) 9 / 12 (+) 15 (=) 27

i don't have anything further cause the post doesn't say it has to continue past "the next number".

Just a bit of fun. I'm not much on math.

##
*[P]Mitt*
December 22 2007 9:58 PM EST

/me patches....

The next number is pi.

Sequence is:

3(n) for n<6, where n is the # term of the sequence

0.523598776(n), where n > or = to 6

:)

##
*Ulord[NK]*
December 22 2007 10:05 PM EST

Let n be the index of the numbers in the sequence.

Let An be the nth number in the sequence.

A1 = 3

A2 = 6

A3 = 9

For An with 6>= n > 3,

An = a*10+b such that a + b = A(n - 3)

A4 = 12, a = 1, b = 2, a+b = 3 = A1

A5 = 15, a = 1, b = 5, a+b = 6 = A2

A6 = 36, a = 3, b = 6, a+b = 9 = A3

Therefore, the 6th number in the sequence is 36.

Finite sequence counts right? :)

Ok, this is a great one, but requires two control variables that are very hard to write out in this forum with no MathType support.

m=-2

n=1

S(k) = n*n - n*m

That's an awesome one...... Works real well, too:

k[1] = 1*1 - 1*-2 = 3

k[2] = 2*2 - 2*-1 = 6

k[3] = 3*3 - 3*0 = 9

k[4] = 4*4 - 4*1 = 12

k[5] = 5*5 - 5*2 = 15

k[6] = 6*6 - 6*3 = 18

k[7] = 7*7 - 7*4 = 21

etc.

btw, that does reduce to:

S(k) = n*n - n*m

S(k) = n ( n - m )

Since n - m is always 3, then it's S(k) = n * 3, or 3n.....

But still... it's cool.

##
*toitle*
December 22 2007 10:52 PM EST

Since I can't win again I have to ruin it for everyone now. The answer is, there is no next number. That is as high as I can count while standing. Think about it a sec, you'll figure it out :)

What, you can't bend down?

S(k) = 3 (5 - n % 5)

Cyclical! The next number is 3!

(% is mod... so (5 - n mod 5))

Wait.. I think there's a typo...

S(k) = n % 5 * 3 + 3, n is 0-based. If n is 1-based, make it (n - 1) instead of (n).

first: even if there is an infinite answers, not necessary for every number to be an answer. e.g. if all multiple of 2s are answers, that would still be infinite.

my answer would be 24. that sequence is actually 2 sequences.

T(2n)=T(2n-2)*2

and T(2n-1)=T(2n-3)+6

where n is any natural number (exclude 0)

##
*Elf X.7plus35k*
December 23 2007 1:56 AM EST

Flexible Mbps increments: 3, 6, 9, 12, 15, 21, 27, 36

##
*Armageddon*
December 23 2007 2:41 AM EST

The one true solution is the segmented line. . .

y=3x; y=integer; x=number position in sequence

Y-Intercept = 0

X-Intercept = 0

Origin of (0,0)

##
*{cb1}Linguala*
December 23 2007 4:05 AM EST

it's 1008

We"re going back in time :-)

Or if you prefer the present, it's 2007

mind the numbers are dividable by 3 and 9

You can add an infinite amount of 0's and 3's, 6's and 9's to any part of a number that's dividable by 3 and it'll stay dividable by 3.

With 9, same goes for 0 and 9.

Or any multiples will do the trick too, so the next number is our fair year of 2007 which is about to make way for another long year(1 extra day in 2008)

I'll have to say... Mitt wins.. sorry, all.

Now for round 2!

the sequence is now 3,6,9,12,15,7218,__

What is the next number?

For this round, I'm only accepting the answer I'm thinking of.

As a hint, the number is between 40,000 and 50,000.

winner gets 200K. (Let's see who's clairvoyant, shall we?)

Meteor Hawk (Tinred Iaeun) 70.18.34.169 Mitt (Mittar) $100000 11:16 AM EST

##
*drudge*
December 23 2007 1:36 PM EST

all yall are ridiculas; nothing in this post made sense at all except the words on the page. ur all insane

yup. CB leads to insanity. We have proven it. It is the purpose of this exercise anyway, right?

The first part: To see if people can follow directions AND think at the same time

The second part: to see if anyone's clairvoyant.

:P

##
*toitle*
December 23 2007 8:54 PM EST

I'll take a stab...42021. the last 2 digits follow what appeared to be the original pattern of 3n, with the entire number divisible by 3n

very close. it's between 43K and 44K

##
*QBOddBird*
December 24 2007 11:54 AM EST

Screw random numbers and clairvoyancy.

The answer is obviously a foot and a half.

You know, I'm surprised noone has typed out all the numbers between 43K and 44K...

I dont have time to write out 1000 numbers so ill guess 2.

43,021

43,420

43121 really, nothing more than random guesses. Does writing a program that prints all number between 43k and 44k counts? It will be in QB (Quick Basic)

43001,43002,43003,43004,43005,43006,43007,43008,43009,43010,43011,43012,43013,43014,43015,43016,43017,43018,43019,43020,43021,43022,43023,43024,43025,43026,43027,43028,43029,43030,43031,43032,43033,43034,43035,43036,43037,43038,43039,43040,43041,43042,43043,43044,43045,43046,43047,43048,43049,43050,43051,43052,43053,43054,43055,43056,43057,43058,43059,43060,43061, 43062, 43063,43064,43065,43066,43067,43068,43069,43070,43071,43072,43073,43074,43075,43076,43077,43078,43079,43080,43081,43082,43083,43084,43085,43086,43087,43088,43089,43090,43091,43092,43093,43094,43095,43096,43097,43098,43099,43100

43101,43102,43103,43104,43105,43106,43107,43108,43109,43110,43111,43112,43113,43114,43115,43116,430

117,43118,43119,43120,43121,43122,43123,43124,43125,43126,43127,43128,43129,43130,43131,43132,43133,43134,43135,43136,43137,43138,43139,43140,43141,43142,43143,43144,43145,43146,43147,43148,43149,43150,43151,43152,43153,43154,43155,43156,43157,43158,43159,43160,43161, 43162, 43163,43164,43165,43166,43167,43168,43169,43170,43171,43172,43173,43174,43175,43176,43177,43178,43179,43180,43181,43182,43183,43184,43185,43186,43187,43188,43189,43190,43191,43192,43193,43194,43195,43196,43197,43198,43199,43200

43001,

43002,

43003,

43004,

43005,

43006,

43007,

43008,

43009,

43010,

43011,

43012,

43013,

43014,

43015,

43016,

43017,

43018,

43019,

43020,

43021,

43022,

43023,

43024,

43025,

43026,

43027,

43028,

43029,

43030,

43031,

43032,

43033,

43034,

43035,

43036,

43037,

43038,

43039,

43040,

43041,

43042,

43043,

43044,

43045,

43046,

43047,

43048,

43049

,43050,

43051,

43052,

43053,

43054,

43055,

43056,

43057,

43058,

43059,

43060,

43061,

43062,

43063,

43064,

43065,

43066,

43067,

43068,

43069,

43070,

43071,

43072,

43073,

43074,

43075,

43076,

43077,

43078,

43079,

43080,

43081,

43082,

43083,

43084,

43085,

43086,

43087,

43088,

43089,

43090,

43091,

43092,

43093,

43094,

43095,

43096,

43097,

43098,

43099,

43100,

43101,

43102,

43103,

43104,

43105,

43106,

43107,

43108,

43109,

43110,

43111,

43112,

43113,

43114,

43115,

43116,

43116,

43117,

43118,

43119,

43120,

43121,

43122,

43123,

43124,

43125,

43126

43127

43128

43129

43130

43131

43132

43133

43134

43135

43136

43137

43138

43139

43140

43141

43142

43143

43144

43145

43146

43147

43148

43149

43150

43151

43152

43153

43154

43155

43156

43157

43158

43159

43160

43161

43162

43163

43164

43165

43166

43167

43168

43169

43170

43171

43172

43173

43174

43175

43176

43177

43178

43179

43180

43181

43182

43183

43184

43185

43186

43187

43188

43189

43190

43191

43192

43193

43194

43195

43196

43197

43198

43199

43200

how about this... next person to post gets 50K and that's the end of the post?

yeah... not at all time-consuming... someone wins something..

I like the idea.

All right. Next person to post wins.

And for a REAL answer, I'd say..43,263

AM I RIGHT? :PO

##
*toitle*
December 24 2007 3:30 PM EST

43221

43200

43201

43202

43203

43204

43205

43206

43207

43208

43209

43210

43211

43212

43213

43214

43215

43216

43217

43218

43219

43220

43221

43222

43223

43224

43225

43226

43227

43228

43229

43230

43231

43232

43233

43234

43235

43236

43237

43238

43239

43240

43241

43242

43243

43244

43245

43246

43247

43248

43249

43250

43251

43252

43253

43254

43255

43256

43257

43258

43259

43260

43261

43262

43263

43264

43265

43266

43267

43268

43269

43270

43271

43272

43273

43274

43275

43276

43277

43278

43279

43280

43281

43282

43283

43284

43285

43286

43286

43287

43288

43289

43290

43291

43292

43293

43294

43295

43296

43297

43298

43299

43300

dang it, i was still typing when u posted

well.. I did say the next person to post would win.. so..

Meteor Hawk (Tinred Iaeun) 141.155.15.186 Fembley (Skyson) $50000 9:16 PM EST

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